Helium 7 nucleus destabilized form
Nuclear structure of

Helium 7
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2p1nHe30.000137 %stable1/2+2 = p+1 - (1n)
2p2nHe499.999863%stable0+2 = 2
2p3nHe5n em7x10-22 s3/2-2 = 1+1 + (1n)
2p4nHe6e em806.7 ms0+2 = 1+1 + (2n)
2p5nHe7n em2.9x10-21 s3/2-2 = 1+1 + (3n)
2p6nHe8e em119.0 ms0+2 = 2 + (4n)
2p7nHe9n em7 zs1/2-#2 = 1+1 + (5n)
2p8nHe102n em2.68 zeps0+2 = 2 + (6n)
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(half life = 2.9 zszepto sec = 10-21 sec ). Move mouse on image for destabilized form of He7 nucleus.

Blue toruses = 7 protons
Red toruses = 5 nuclear electrons

Atomic number of He (2) = protons (7) - nuclear electrons (5)

Helium 7 decays by neutron emission (from the left side) of Helium 7 destabilized form to Helium 6 and

Helium 6 decays by electron emission (left side electron) of Helium 6 destabilized (decay) form to Lithium 6 (stable) nucleus (100%) or

Helium 6 decays (in a small fragment) by electron emission followed by deuterium emission and rest of He4.

Click on image for Helium 6 nucleus


Yin-yang model of photon and matter
Structures of atomic nuclei of elements


Helium 6 nucleus Helium 8 nucleus

He3He4He5He6He7He8He9He10

HHeLiBeBCNOFNe
NaMgSiSArCaFeNiNdPb

 
Toroidal atomic nuclear structure of Helium 7 isotope decay by neutron emission into Helium 6 nucleus, then electron emission as beta radiation into Lithium 6 stable isotope nucleus. Electron ejected at end of torus rod.
 
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