Boron 9 destabilized nuclear structure
Nuclear structure of

Boron 9
5p2nB7p em0.32 zeps3/2-5 = 3p+2 - (3n)
5p3nB8b+770 ms2+5 = 2p+3 - (2n)
5p4nB9p+2He em8x10-19 s3/2-5 = 1p+4 - (1n)
5p5nB1019.8 %stable3+5 = 3+2
5p6nB1180.2 %stable3/2-5 = 1+4 + (1n)
5p7nB12e em, 3He em20.20 ms1+5 = 2+3 + (2n)
5p8nB13e em17.33 ms3/2-5 = 3+2 + (3n)

(half life = 8x10-19 s). Move mouse on image for Boron 9 destabilized form.

Blue toruses = 9 protons
Red toruses = 4 nuclear electrons

Atomic number of B (5) = protons (9) - nuclear electrons (4)

Boron 9 decomposes by proton emission (100%) with double alpha decay as
central proton of Boron 9 destabilized and forms two He4 nucleus (alpha particles).

After proton emission from the end of nuclear nanotube the instable B8 splitted and two alpha particles liberated.

See Be8 decay (half life = 6.7x10-17 s), two alpha particles are not stable.

Structures of atomic nuclei
Photon model of light

Boron 8 nucleus Boron 10 nucleus




Boron 9 or B9 isotopes nuclear structure and decomposition of Boron9 nucleus into proton and two alpha particles. Decay mechanism of decomposition. The first step of decay is a proton emission from one of the end of nuclear rod in B9 torus model.