Boron 8 nucleus decay form
Nuclear structure of

Boron 8
.ooOOoo.
5p2nB7p em0.32 zeps3/2-5 = 3p+2 - (3n)
5p3nB8b+770 ms2+5 = 2p+3 - (2n)
5p4nB9p+2He em8x10-19 s3/2-5 = 1p+4 - (1n)
5p5nB1019.8 %stable3+5 = 3+2
5p6nB1180.2 %stable3/2-5 = 1+4 + (1n)
5p7nB12e em, 3He em20.20 ms1+5 = 2+3 + (2n)
5p8nB13e em17.33 ms3/2-5 = 3+2 + (3n)
...
 

(half life = 770 ms). Move mouse over image for B8 nucleus transition form.

Blue toruses = 8 protons
Red toruses = 3 nuclear electrons

Atomic number of B (5) = protons (8) - nuclear electrons (3)

Boron 8 transform by electron capture (from light !) of B8 nucleus transition form and Be8 nucleus generated (half life = 67 as).
The electron comes from a photon pair production and the rest of a positron emanated.

Be8 nucleus shortly decay further by splitting of Beryllium 8 into two He4 particles.

Click on image for Be8 nucleus decay.


Photon model of light
Structures of atomic nuclei


Boron 7 nucleus Boron 9 nucleus

B7B8B9B10B11B12B13B14B15B16B17

HHeLiBeBCNOFNe
NaMgSiSArCaFeNiNdPb

 

Decay of Boron 8 forms matastable Berillium8. Repulsive magnetic forces act between two half of the Be8 nucleus. He4 emission through Berillium 8 results in two alpha particles are He4 nuclei. It may be interesting if b+ isotopes would lights up with appropriate vawelengths of gamma photon. May it be used for decontamination of radioactive isotopes?


 
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